Why on pointer addition we go to the next address?
if xptr=2045
then xptr+1 should give me 2046 and not 2049 as I have added 1 and not 1*sizeof(int)
Pointer addition doubt
you are not adding integers which gives 2047 on adding 1 to 2046
Unlike regular numbers, adding 1 to a pointer will increment its value (a memory address) by the size of its underlying data type. To simplify the logic behind this, think of pointer arithmetic the same way you think about array indexing. If we declare an array of ten integers int numbers[10] , we have a variable that has reserved enough memory to hold ten int values. With int taking up 4 bytes, numbers is 40 bytes in total, with each entry 4 bytes apart. To access the fifth element, we simply write numbers[4] and don’t need to worry about data type sizes or addresses. With pointer arithmetic, we do the exact same thing, except the array index becomes the integer we add to the pointer, (numbers + 4) .
also there is no point of adding 1 to pointer(2016) and getting 2047
it is not the starting address of any data
next address which is possible for any data will be 2050
i hope this help
if you have more doubts regarding this feel free to ask
if your doubt is resolved mark it as resolved from your doubt section inside your course
I hope I’ve cleared your doubt. I ask you to please rate your experience here
Your feedback is very important. It helps us improve our platform and hence provide you
the learning experience you deserve.
On the off chance, you still have some questions or not find the answers satisfactory, you may reopen
the doubt.