Pls find the error in code

#1

#include

#include
using namespace std;
int main(){
int N;
cin>>N;
int n;
for(int i=1;i<=N;i++){
cin>>n;

int s=0;
while(n>0){
    int x=n%10;
    s++;
    n=n/10;
    
    
    
        
    }
    
    
    
    
    

if(s%2==0){
    int k=0;
    while(n>0){
        int x=n%10;
        k=k+x;
        n=n/100;
    }
    if(k%4==0){
        cout<<"YES"<<endl;
       
        
    }
    
    else{
        cout<<"NO"<<endl;
    }
}
else{
    int k=0;
    while(n>0){
        int x=n%10;
        k=k+x;
        n=n/100;
    }
    if(k%3==0){
        cout<<"YES"<<endl;
        
    }
    else{
        cout<<"NO"<<endl;
    }
}
}   
}
#2

hi @sanat23122003_d46801d36f7a8d94,
u need to find the sum of even digits in the no (say SUM1) and sum of odd digits in the no (say SUM2)
then if SUM1 is div by 4 or SUM2 is div by 3 you can print yes

eg : 1235
SUM1 = 2; --> not div by 4 (failed)
SUM2 = 1 + 3 + 5 --> 9 --> div by 3 (passed)

any one passes print yes

u can refer the the code if having difficulties in implementation https://ide.codingblocks.com/s/657615

#3

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