Please tell my how this program flow work

#1

Q­6 What will be the output of the following program? #include
using namespace std;
int main() {
int arr[]={0,1,2,3,4};
int i, ptr;
for(ptr= arr, i=0; ptr+i <= arr+4; ptr++, i++) cout<<(ptr+i);
return 0;
}
A) 01234
B) 024
C) 234
D) 12340
why it printing 024 instead of 01234

#2

Hello @dkroy8790,

NOTE:

  1. The name of the array act as the pointer to the first element of the array.
  2. (array_name +i) refers to i location ahead of the location pointed by array_name

Now, coming to the execution:

  1. initially:
    ptr points to location of 0 and i=0
    so, *(ptr+0)=0

  2. ptr after increment points to 1 and i=1
    so, *(ptr+1)=2

  3. ptr after increment points to 2 and i=2
    so, *(ptr+2)=4

  4. ptr after increment points to 3 and i=3
    but, (ptr+i) is a location ahead of(or greater than) the address of (arr+4)
    Terminating loop.

Hence, the ouput is: 024

Hope, this would help.
Give a like if you are satisfied.

#3

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