Since the function perceptron represents is
y= | z>=threshold 1 |
| z< threshold 0|
If this is the case and the function is x1.x2.x3’.x4’
and x2 inputs x3 and x4 are inverted
then the output must be high for input [1 1 0 0]
and the X3 and X4 be inverted to give [1 1 1 1] whose sum must be 4 otherwise the function must be zero. If my reasoning is correct then 4 should be the answer . please explain
Hey @Lakshita, you are taking wrong meaning of statement “Note that circle at the end of x3 and x4 input n the diagram depicts it is an inhibitory input i.e. if this input is 1 then the output will be 0 for sure irrespective of other inputs)”
It doesn’t mean that x3 and x4 will be negated and than given to perceptron. The statement means whenever x3 = 1 or x4 = 1 the final output of perceptron will be 0 no matter what are the other inputs.
by this case only these four cases are left
x1 x2 x3 x4 output
0 0 0 0 0
0 1 0 0 0
1 0 0 0 0
1 1 0 0 1
For all rest cases output will be directly zero no need to worry about them. From here you can see that threshold value must be 2.
Hope this resolved your doubt.
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