 # Please can u tell the error in my code?

Raj is a very smart kid who recently started learning computer programming. His coach gave him a cyclic array A having N numbers, and he has to perform Q operations on this array. In each operation the coach would provide him with a number X. After each operation, every element of the cyclic array would be replaced by the sum of itself and the element lying X positions behind it in the cyclic array. All these replacements take place simultaneously. For example, if the cyclic array was [a, b, c, d], then after the operation with X = 1, the new array would be [a+d, b+a, c+b, d+c]. He needs to output the sum of the elements of the final array modulus 10^9+7. He made a program for it but it’s not very efficient. You know he is a beginner, so he wants you to make an efficient program for this task because he doesn’t want to disappoint his coach.

Input Format
The first line of each test file contains a integer N. The next line contains N space separated integers which represent the elements of the cyclic array. The third line contains a integer Q representing the number of operations that will be applied to the array. Finally, Q lines follow, each one containing an integer X .

Constraints
1 <= N <= 100000
1 <= Ai<= 10^9
0 <= Q <= 1000000
0 <= X < N

Output Format
Your program should output to the standard output stream the sum of the elements of the final array modulus 10^9+7.

Sample Input
5
1 2 3 4 5
2
1
0
Sample Output
60
Explanation
After the 1st operation (X = 1), the array would be [1+5, 2+1, 3+2, 4+3, 5+4] =[6, 3, 5, 7, 9]
After 2nd operation (X = 0), the array would be [6+6, 3+3, 5+5, 7+7, 9+9] =[12, 6, 10, 14, 18]
Thus the correct answer would equal to = (12+6+10+14+18) % (10^9+7) = 60

MY CODE:#include
using namespace std;
int main() {
int n;
cin>>n;
int a[n],arr[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
int q;
cin>>q;
int x,i;
cin>>x;
for(int j=0;j<q;j++){
for(int i=0;i<n;i++)
{ if (i-x>=0){
arr[i]=a[i-x];}
else if((i-x<0)&&(n-i+x<n))
{
arr[i]=a[n-i+x];}
else {int k=n-i+x;
while(k>=n){

``````					k=k-n;
}
arr[i]=a[k];

}

}
x=x-1;}
int sum;
for(int p=0;p<n;p++){
sum=sum+arr[p];
}
cout<<sum%(10^9+7);
return 0;
``````

}

refer https://ide.codingblocks.com/s/662778 ive commented the code