Phone keypad problem

#1


when giving input in terms of 0 or 1 permutation no output is coming example 10 or 51 rest is fine

#2

when the target value == 0 or 1
then simply call the function by increasing the pointer in __in __array while keeping the j pointer on the same position since nothing is added

#3

but why this is happening i want to know logic…

#4

since , we there is no character at map[0] & map[1] so basically the for loop doesnt run, hence the code would not proceed furthur, and no recursive call will be made at this point ,
hence in order to prevent overflow, we make a call to the next character in the input array .
so that the code progresses and the remaining characters are processed

#5

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