Pattern Hour Glass

#1

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int nr = 2 * n + 1;
int nst = nr;
int nsp = 0;

	int row = 1;
	while (row <= nr) {
		int val = 5;

		for (int csp = 1; csp <= nsp; csp++) {
			System.out.print(" ");
		}

		for (int cst = 1; cst <= nst; cst++) {

			if (cst <= nst / 2) {
				val--;
			} else {
				val++;
			}
			System.out.print(val);

		}
		
		System.out.println();

		if (row <= nr / 2) {
			nsp=nsp+1;
			nst=nst-1;
		} else {
			nsp=nsp-1;
			nst=nst+1;
			
		}
		row++;
	}
}

Please help me in this . this the code for pattern hour glass

#2

@amangaur078,

Pattern Hack : Always first Try to first print pattern by ignoring the value to be printed then accommodate your value in that pattern. For e.g.,

                      5 4 3 2 1 0 1 2 3 4 5
                        4 3 2 1 0 1 2 3 4 
                          3 2 1 0 1 2 3 
                            2 1 0 1 2 
                              1 0 1 
                                0 
                              1 0 1 
                            2 1 0 1 2 
                          3 2 1 0 1 2 3 
                        4 3 2 1 0 1 2 3 4 
                      5 4 3 2 1 0 1 2 3 4 5

View it as:-

                      * * * * * * * * * * *
                        * * * * * * * * * 
                          * * * * * * * 
                            * * * * * 
                              * * * 
                                * 
                              * * * 
                            * * * * * 
                          * * * * * * * 
                        * * * * * * * * * 
                      * * * * * * * * * * *

Given pattern is seen as first spaces and then numbers.The numbers are first in in decreasing order and then in increasing order in a row. Spaces first increases and then decreases in a row. So do the work of spaces first and then that of numbers.And then change variables accordingly for next iterations.

#3

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