Pair wise swaping n-itr-1

#1

i didnt understand why we need just n-itr-1 iteration in j for loop

#2

because with each itr, array is sorted at last,
that is
for itr=0, largest element is there at arr[n-1]
for itr=1,second largest element is there at arr[n-2]
and so on,
so we don’t need to go till end always!

#3

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