Operation on pointers

#1

sir can you explain it with example

Addition of an address by a constant integer value i.e. ptr +5 means
address of cell which is 5 * sizeof(*ptr) away from ptr.

#2

@Ankit_123
You are right. When we write ptr = ptr + 5 , where ptr is a pointer , it moves 5 steps ahead where each step is of the size = sizeof(*ptr).
Take a look at this little example as I think it might help you out.

#include < iostream >
using namespace std;
int main() {
int A[ ] = {1,2,3,4,5,6,7,8,9,10};
int n = 10;

int *p = A;

cout << *p << endl;     //1 ... as p is at the first location of the array A

p = p+2;        //Move p two steps ahead , to the box containing data 3

cout << *p << endl;     //Prints 3

p = p+5;       //p moves 5 steps ahead to the box containing 8.

cout << *p << endl;     //Prints 8

return 0;

}

#3

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