One test case fails please explain the error in the code

#1

#include
using namespace std;
void find(long long int num){
long long int m=num;
if(m==0){
cout<<5;
}
else{
int i,counter=1,sum=0;
for( i=0,m;m!=0;m/=10,i++){
int r=m%10;
if(r==0){
r=5;
}
sum+=rcounter;
counter=10;
}
cout<<sum;
}

}
int main(){
long long int num;
cin>>num;
find(num);

return 0;

}

#2

hi @nitinchauhan0808_be04315530401452
corrected code–>

#include <iostream>
using namespace std;
void find(long long int num){
    long long int m=num;
    if(m==0){
         cout<<5;
    }
    else{
        long long int i,counter=1,sum=0;
        for( i=0,m;m!=0;m/=10,i++){
            int r=m%10;
            if(r==0){
                r=5;
            }
            sum+=r*counter;
            counter*=10;
        }
        cout<<sum;
    }
    
}
int main(){
    long long int num;
    cin>>num;
    find(num);
    
    return 0;
}
#3

long long int i,counter=1,sum=0;
this change was required.

#4

sir but why long long int is used in i.i is just a iterator in the loop

#5

what is the use of long long int in i?

#6

basically long long int is need for the sum=0, but since u have declared 3 variables together, make int as long long int. Or seperately write as long long int sum = 0;

#7

Hey, is there anything else??

#8

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