Odd and even back in delhi

#1

The question is not at all understandable . Please explain what we have to do in this question by some example . I am not asking for solution just asking you to explain the questiom

#2

what is not understandable in this question?

this is straight forward problem

for each carNo you have to check this condition

if the sum of digits which are even is divisible by 4 or sum of digits which are odd in that number is divisible by 3.

first calculate sum of even digit(evenSum) and sum of odd digits(oddSum)
now check

if(evenSum%4==0 || oddSum%3==0)
   cout<<"Yes";
else 
   cout<<"NO";