Not understand whole solution

#1 
printWords(n/10);         ???
int digit = n%10;       ????
cout << words[digit]<<" ";       ?????
#2

hello @amit0001

first understand this .
a)
if number is 1234 then 1234/10 = 123 (ie dividing by 10 will remove right most digit from the number).

b) if number is 1234 then 1234%10= 4 (ie taking mod with 10 ,will give right most digit of the number)

now come to recusion .
we receive a number N.
we remove rightmost digit and call recusion on remaining numbers
after that once the execution of subproblem is done we print the right most digit.

#3

why we take a 2D array?

#4

it is for storing words.
the words are stored something like this->
ss

thats why we need 2d array.

#5

okay thank you
I mark as resolve

#6

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