Not confusion in recursive calls

#1

where is a small-head and head after hitting the base case ?

#2

Hi @amit0001… pls share the code snippet u are referring to

#3

if (head->next == NULL || head == NULL)

{

    return head;

}

Node *small_head = reverseRecursively(head->next);
#4

why small head is != second last node. after returning from base case head = secondlast node

#5

at the end :point_down: :point_down:
reverseRecursively(head->next) =secondlast node ?;

#6

confusion in recursion

#7

r u there @Vaibhav277

#8

basically *small_head stores the head of the linked list reversed recursively

#9

I hope ur doubt is cleared

#10

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