Not able to solve this ,here is my code

#1

#include
using namespace std;
int main() {
int num;
cin>>num;
int sum_even=0;
int sum_odd=0;

while(num>0){
	if(num%2==0){
		sum_even = sum_even + num;
	}else{
		sum_odd = sum_odd + num;
	}
	if(sum_even%4==0 || sum_odd%3==0){
		cout<<"YES"<<endl;
	}else{
		cout<<"NO"<<endl;
	}
}
return 0;

}

#2

hello @anuragsen9617
u have misunderstood the statements.

u need to compute sum of even digits and sum of odd digits seprately .
and after that if sum of even digits is divisbile by 4
or if sum of odd digits is divisible by 3 then u need to print yes otherwise no.
refer this->

#3

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