Need another method

#1

i need to slove with any other method because im not getting this one.

#2

@kumarankit3450 you can do this:
create another string/char-array, put first element into it
then have a pointer at 1(let x=1)
now just ignore all elements which are repeating, this can be checked by
while(x<n and arr[x]==arr[x-1])
x++;
this loop exits either when x=n(reached end) or when a new character comes.
so this is final pseudo code:
x=0
y=0
while(x<n){
ans[y]=arr[x]
x++
y++
while(x<n and arr[x]==arr[x-1])
x++;
}

#3

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