Modulo division property

#1

Can you write the code for finding the " b inverse " as mentioned in this video?

#2

I think to find b inverse all you have to do is take it as (1/b) in the formula which can be written as-> (a/b)%m=((a%m)*((1/b)%m))%m. In this way, we prevent ourselves from encountering a case where (b%m) can become infinite, thus giving an infinite answer, hence being reason for not writing the formula as (a/b)%m=((a%m)/(b%m))%m.

#3

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