MCQ pointer pdf

#1

please expalain the solution of question 7

#2

2d array can be represented in the following way as well

To access an individual element of our 2-D array, we should be able to access any jth element of ith 1-D array.
Since the base type of *(arr + i) is int and it contains the address of 0th element of ith 1-D array, we can get the addresses of subsequent elements in the ith 1-D array by adding integer values to *(arr + i).
For example *(arr + i) + 1 will represent the address of 1st element of 1stelement of ith 1-D array and *(arr+i)+2 will represent the address of 2nd element of ith 1-D array.
Similarly *(arr + i) + j will represent the address of jth element of ith 1-D array. On dereferencing this expression we can get the jth element of the ith 1-D array.
#3

after understanding this you will be able to figure out the sum of elements on diagonal is being calculated (i.e arr[i][i] (arr[1][1],arr[2][2], arr[3][3]) )

#4

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