Math probability 3 quiz

In how many ways 5 men and 3 women can sit together on a circle such that a particular men m1 and particular women w1 never sit adjacent to each other?

How is the question solved?

hello @bishal_c

solve it using includion exclusion.

they dont sit together= total ways - they sit together.

     = 7! - 6!*2  (into 2 because  they themselves can  change their position with each other)

got it… thank you :slight_smile:

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