Manmohan loves pattern 1

#1

won’t be able to understand this please give me anther logic for this q

#2

Did you understand how the pattern is being formed?

#3

no please explain me in easy way whole program

#4

The number of values in each row = number of that row. And now if you look carefully, the odd-numbered rows only contain 1 and the even-numbered rows contain 1 at extremes only.
Try to code using this logic. It is an easy question.

#5

why after if and else block we are using while loop

#6

why can’t we direct solve it I don’t understand please clear the process

#7

please reply me fast

#8

please reply me why after if and else we are using while loop please reply me fast

#9

and also in else statement why row-2 is used I won’t be able to understand please Clear my doughts

#10

Send your code please

#11

the same code which is solved in he video why col<=row-2 used

#include
using namespace std;
int main()
{
int n;
cin>>n;
int row=1;
while(row<=n){
int col=1;
if(row%2!=0){
while(col<=row){
cout<<1;
col=col+1;

    }
    }
    else{
        cout<<1;
        while(col<=row-2){
            cout<<0;
            col=col+1;
        }
        cout<<1;
    }
    cout<<endl;
    row=row+1;
}
return 0;

}

#12

and why if else statement while loop is used explain me in full detail

#13

First of all, did you dry run this code on the sample input?

#14

col<=row-2 is because in the even numbered rows, we want to have 2 1s and row-2 0s.

#15

Loops are used when we want to repeat a set of statements.

#16

why int row=1 and after loop of row we are inputing int col=1; why not before loop we are inputing both row and col =1; why col is written after row<=n after that why please explain me

#17

please reply me fast

#18

hey please reply me fast

#19

You can declare the variable col outside the while(row<=n) as well. But it is necessary to reset col to 1 because for every row, we have to start from its first column.

#20

so how I do if I am taking before I won’t be able to do please do a program and explain me