Mamohan loves pattern

#1

Explain the test case in whic i failed

#2

@guptakanwal30 you have to take user input for N and then print the pattern according to the value of N. Right now you are only printing for n = 6 and not taking any input

#3 
	Scanner scn=new Scanner(System.in);
	int n=scn.nextInt();
	int str=1;
	int csp=0;
	if (n<=1000) {
	System.out.println("1");
	for(int row=1;row<=n-1;row++) {
		for(int st=1;st<=str;st++){System.out.print("1");}
		for(int sp=1;sp<=csp;sp++){
			if (row%2==0)
			
			System.out.print("1");
			else 			System.out.print("0");
		}
		for(int st=1;st<=str;st++){System.out.print("1");}
		System.out.println("");
	csp=csp+1;
	}}
	
	else {
		System.out.print("INVALID");
	}

}}

#4

@guptakanwal30 do you still need any help with this question?

#5

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