m * n = N / 2 How can we take m = N / 2 and n = 1
M,n value substitution?
Hi @sahazeer123, In this question we will be given N that is either the base or height of a triangle and we need to find triplet satisfying the pythagoras theorum
So, u know that if we have two numbers m and n then we can definetly find a triplet that will satisfy the pythagoras theroum and the triplet will be
(m^2-n^2 , 2*m*n , m^2+n^2)
Here we are sure that m^2+n^2 is hypotenues
so the given number N can be either (m^2-n^2) or 2mn
Since you need to find only one triplet , so what u can do if n is even we can write it as 2 * X
if find m and n satisfying m*n=X then we can find the triplet so, if we take m=1 or n=1 then other will be X thus we know m and n thus we get the triplet . I hope u got what i am saying .
As we need to find one such value of m and n that can satisfy m*n=(N/2) we can take N/2 as m and 1 as n
In case of any doubt feel free to ask 
If you got the answer make sure to mark it resolved
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