Linked list memory managment

#1 
                even->next = temp->next;  ------>  1
                even = temp->next;        ------>  2

Is this statement correct? In (1) temp->next value gets assigned to even->next, it means the data is lost from temp->next. So, we can put even = temp->next again.

#2

hello @yogeshcsc20

no , data will not lost.

it depends on exaclty what u r trying to achieve

#3

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