Lexicographical sorting

#1

how to lexicographically sort int and string ,can you plz make a compare function for this.

#2

If you want the default ascending order sort.
You can do something like this
string name=“ahdhkjc”
sort(name.begin(),name.end())

For other sorting configurations, you can use your own custom comparator as desired.

#3

actually if we want to sort let’s say 112,12 so we get the order 12 follwed by 112

#4

how to make compare function for this

#5

12,112 is in ascending order.
So by default it will be sorted in this order without using any compare function

#6

bool compare(int a,int b)
{
return a>b;
}

int arr[3]={1,11,121}
sort(arr,arr+3)

In this way you can sort in descending order

#7

but lexicographically 12 is greater than 112 and i want to know how to compare lexicographically and make its function

#8

i m not asking for aceding or decending order of array

#9

For such case convert the number to string or take input the number in a string variable
You can convert integer to a string by using inbuilt to_string function and then use the sort function. It will then sort it lexicographically

#10

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