Last test case not passing

#1

#include
using namespace std;
int main() {

int n;

cin>>n;
int a[n];
for(int i=0;i<n;i++)
{
cin>>a[i];
}
cout<<a[0]<<" ā€œ;
for(int i=n-1;i>0;iā€“)
{
cout<<a[i]<<ā€ ";
}

return 0;

}

#2

reversing and inversing array are 2 different things
here you have to inverse, not reverse

Inverse is Simply swapping the value of the array with the value at that index.

Algo

  1. Create a new Array say narr and original array is arr.
  2. now at the arr[i]th index of narr save the ith value.(previously i is the index and arr[i] is the value bt now arr[i] is the index and i is the value.)
  3. return new array.

refer this code -->

#include<iostream>
#include<bits/stdc++.h>
using namespace std;
int main() {
	int N;
	cin>>N;
	int a[N];
	for(int i =0;i<N;i++)
		cin>>a[i];
	int b[N];
	for(int j=0;j<N;j++){
		b[a[j]]=j;
	}
    for(int i=0;i<N;i++){
        cout<<b[i]<<" ";
    }
	return 0;
}
#3

but this solution only works if values array elements contains all the index values. Suppose if a[i]=100 and size of array is 5 then this solution will fail

#4

if you are finding inverse of array then this will never happen
array element must be from 0 to n-1

kindly check again it is passing all testcases