Is there any alternative way to solve this problem

#1

#include
using namespace std;
int main() {
int r,s=0,t=0,n,c;
cin>>n;
c=n;
while(n!=0)
{
r=n%10;
s=s+r;
n=n/100;
}

while(c!=0)
{
    r=c%100;
    r=r/10;
    t=t+r;
    c=c/100;
}

cout<<s<<"\n" ;
cout<<t;

return 0;

}

#2

Hi @abhishekpandeybhu_da87a9e0d2c73079
Ur approach is absolutely fine… the only way is to extract digits and then compute ans… u do the whole process using a single while loop only, no need for 2 loops…

#3

Hey, is there anything else??

#4

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