Inverted hour glass

#1

how to approach this

#2

@anmolsr755
Hello Anmol,
break each line into three parts

numbers then some spaces and then again numbers.
image

#3

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#4

import java.util.Scanner;

public class invertedhourglass {

public static void main(String[] args) {
	Scanner sc = new Scanner(System.in);
	int n =sc.nextInt();
	int nst =1;
	int nsp=2*n-1;
	int nr=2*n+1;
	int val1;
	int val2;
	
	//row
	int row=1;
	while( row<=nr)
      {
		val1=5;
		val2=1;
		for (int cst=1;cst<=nst;cst++){
			if(cst<=nst){
				System.out.print(val1-- + " ");
			}
		}
		
		for (int csp=1;csp<=nsp;csp++){
			System.out.print("  ");
		}
		int cst=1;
		if (row==n+1){
			cst=2;
		}
		
		for (;cst<=nst;cst++){
			if(cst<=nst){
			System.out.print(val2++ + " ");

			}
		}
		
		
		
		
		System.out.println();
		if(row<=nr/2){
			nst=nst+1;
			nsp=nsp-2;
		}
		else{
			nst=nst-1;
			nsp=nsp+2;
		}
		row=row+1;
	  }

}

}

This is my code and I am not getting how to insert value in second side of the pattern. Please check it and let me know