Inverse of an array

#1

i want the approach like how is array inverted. basically i want to get the example of an array before inversion and after inversion

#2

inverting a array mean

if in original array arr[i] is at ith position then
in inverted array i will be present at arr[i] th position

consider this example
5
4
0
2
3
1

4 is at 0st position so in ans Array 0 will be at 4th position
similarly
0 is at 1st position so in ans Array 1 will be at 0th position
2 is at 2st position so in ans Array 2 will be at 2th position
1 is at 4st position so in ans Array 4 will be at 1th position

Sample Output
1 4 2 3 0

i hope now question is clear

Solution

Inverse is Simply swapping the value of the array with the value at that index.

Algo

  1. Create a new Array say narr and original array is arr.
  2. now at the arr[i]th index of narr save the ith value.(previously i is the index and arr[i] is the value bt now arr[i] is the index and i is the value.)
  3. return new array.

refer this code -->

#include<iostream>
#include<bits/stdc++.h>
using namespace std;
int main() {
	int N;
	cin>>N;
	int a[N];
	for(int i =0;i<N;i++)
		cin>>a[i];
	int b[N];
	for(int j=0;j<N;j++){
		b[a[j]]=j;
	}
    for(int i=0;i<N;i++){
        cout<<b[i]<<" ";
    }
	return 0;
}
#3

clear thanks for explaining

#4

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#5

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