Inverse of an array: last test case error. Problem in the code?

#1

#include
using namespace std;
void reverse(int a[],int start, int end){
if(start<end){
if(start==0){
reverse(a,start+1,end);
}
else if(end==0){
reverse(a,start,end-1);
}
else{
int temp = a[start];
a[start] = a[end];
a[end] = temp;
start++;
end–;
reverse(a,start,end);
}
}
}
int main() {
int n;
cin >> n;
int a[n];
for(int i=0; i<n; i++){
cin >> a[i];
}
reverse(a,0,n-1);
for(int i=0; i<n; i++){
cout << a[i] << " ";
}
}

#2

don’t confuse inverse with revers
reversing and inversing array are 2 different things
here you have to inverse, not reverse

Inverse is Simply swapping the value of the array with the value at that index.

Algo

  1. Create a new Array say narr and original array is arr.
  2. now at the arr[i]th index of narr save the ith value.(previously i is the index and arr[i] is the value bt now arr[i] is the index and i is the value.)
  3. return new array.

you can refer this code

#3
#4

i think you mistakenly shared your code here

i hope your doubt on inverse of array is cleared
so kindly give feedback
if not feel free to ask

#5

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