Invalid literal for int with base 10

#1

How do i resolve this error?

1920Ă—1080 207 KB

#2

Hello @gunjanarora, the way you have taken the input is incorrect.
The 1 10 denotes that the input taken is in the single line. So you need to take, lower,upper = map(int,input().split())
Pls, try this out and if it doesn’t work pls let me know.
Thanks :slight_smile:

#3

The error message invalid literal for int() with base 10 would seem to indicate that you are passing a string that’s not an integer to the int() function . In other words it’s either empty, or has a character in it other than a digit. You can solve this error by using Python isdigit() method to check whether the value is number or not. The returns True if all the characters are digits, otherwise False .

val = "10.10"
if val.isdigit():
  print(int(val))

Python2.x and Python3.x

Sometimes the difference between Python2.x and Python3.x that leads to this ValueError: invalid literal for int() with base 10 .

With Python2.x , int(str(3/2)) gives you “1”. With Python3.x , the same gives you (“1.5”): ValueError: invalid literal for int() with base 10: “1.5”.