Instead of 0 3 1 4 2 i am getting 0 3 1 4 3 as output

#1

Take as input N, a number. Take N more inputs and store that in an array. Write a recursive function which inverses the array. Print the values of inverted array

Input Format
Enter a number N and take N more inputs

Constraints
None

Output Format
Display the values of the inverted array in a space separated manner

Sample Input
5
0
2
4
1
3
Sample Output
0 3 1 4 2

My code:
#include
using namespace std;
int main() {
int n;
cin>>n;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
int i=0;
while(i<n){
a[a[i]]=i;
i=i+1;
}

for(int i=0;i<n;i++){
	cout<<a[i]<<" ";
}
return 0;

}

#2

@alokkr2111_c44918384e4c5a59 , Hi use 2 array else you r changing the content of original array
Logic: Inverse is Simply swapping the value of the array with the value at that index.

Algo
Create a new Array say narr and original array is arr.
now at the arr[i]th index of narr save the ith value.(previously i is the index and arr[i] is the value bt now arr[i] is the index and i is the value.)
print new array.
here’s the updated code https://ide.codingblocks.com/s/659002

Sample Input
5
0
2
4
1
3
Sample Output
0 3 1 4 2

here it means 0 will be in 0 index
1 in 2
2 in 4
3 in 1
4 in 3

#3

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