Increment Operator

#1

i = i++ + ++i

How to solve it?

#2

Hi @ssinha2103
lets consider a test case… let initially i be 2…
now u are performing i = i++ + ++i;
so when i++ is performed it is post increment… which means initially value of i remains same and is used for computation and then value of i is incremented by 1… so in my ans 2 would be added and i becomes 3…
now when ++i is performed it means pre increment, ie increase value of i by 1 first then use it for computation… thus i becomes 4… now when u add it to our ans 2 + 4 comes out to be 6 and that value is assisgned to i varible…
u can also try running the same code in ide with test case 2, u will get the same ans ie 6…
i hope it clears all ur doubts…

#3

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