In deep copy concept , i have a doubt

#1

in the video ,
the code is
Car(Car &X)
{ …
name = new char[l+1];
strcpy(name,X.name);
}
Doesnt this also create a shallow copy. as first you the pointer name contains the address of a new array , but then we copy the address contained by X.name into name. so the address of the new array gets overwritten

#2

@Anchal
strcpy( ) doesn’t copy the address of the array. It copies the data in that array. So the data of X.name gets copied to name . Both the pointers however still retain their original addresses.

#3

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