If I assign the address of a variable to int variable

#1

If I assign the address of a variable to int variable, and then output it, will I still get result in hexadecimal form?
Eg.
int x=10;
int address=&x;
cout<<address;

//What will be the output?

#2

hello @Ayush280301
compiler will give errors because of invalid conversion.

int addresss=&x;
here &x will give address but address is integer variable ie compiler will only allow integer value in it…
u need to declare address as pointer and then it will work.

#3

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