If f(n)=loga(n)+logb(n) , a>b>1, then

#1
  1. f(n) is O(loga(n))
  2. f(n) is O(logb(n))
  3. Both of the above
  4. None of the above
    What is the correct answer to the question. Please help me with explanation
#2

Hello @kodivine0,

The answer should be 2.

Reason:
for e<10, ln(10)>log(10).
So, same way loga(n)< logb(n) for a>b.

Hope, this would help.

#3

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