I have use this approach to solve this problem is it a bad approach in interview time to solve this problem

#1

// code part

public static Boolean checkSum(int n){
	
	for(int i=0;i<10005;i++){
		int sum = 0;
		while(n>0){
			sum += Math.pow(n%10,2);
			
			n = n/10;
		}
		if(sum==1){
			return true;
		}
		n = sum;
	}
	
	return false;
	
}

}

#2

no… there is nothing wrong in ur approach… all u have to just check is if sum !=1 u will again assign it to n do that process again until some repetition is there…

#3

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