I got the logic but why did this code does not works if i use 1d array
and when we print the array why do we only pass one parameter to the array
I dont get how the 2d array works in this case
Hey @tAkshat one d array is not Enough as It will store only single alphabet but no words. Whereas 2 d array stores alphabets with words
That’s a default property suppose in your words[1] will be having a complete string “one” in which
words[1][0]='o'
words[1][1]='n'
words[1][2]='e'
words[1][3]='\0'
so if you will do cout<<words[1] it will print ‘one’ till null character, that’s a property of 1d char array.
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