How is the output array being printed?

#1

Where are we actually printing the subsequences for the recursive case since ‘cout’ is used when in[i]==’\0’ i.e. in the base case.

#2

whenever the length of the input sequence becomes 0 or(it reaches ‘/0’) a new sub sequence is generated and we print that in the cout statement

#3

Yes, but on the previous line, we declare output array to be zero, then printing it out doesn’t make any sense.

#4

can you please show the line you are talking about or share your code

#5

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