HOW is if(j&1) used for checking for odd no

#1

HOW is if(j&1) used for checking for odd no.
time: 01:24:25

#2

Numbers are stored binary numbers, and all odd numbers have least significant bit 1, so odd &1 =1 and even&1=0 (as least significant bit is 0 for even number, and 1 has only 1 bit, eg 2&1=0(10&1)).

#3

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#4

and why do we need cin.ignore(); i tried without it is only taking n-1 string even when i made the code run for n times.