How does this work?

#1

look at my code:
int main()
{
int a;
a=(5/9)*2;
cout<<a;
return 0;
}
here it would print 0. if i change 9 to 9.0 , still it prints 0. But if i change both 5 and 9 to 5.0 and 9.0 then it prints 1.

why?

#2

this is because of implicit type conversion
and also because you are storing float value in a int bucket

i have explained all combination in code
first you look at code and read the explanation and then run it and check the output with your understanding

Example Code

#include <iostream>
using namespace std;
int main() {

    cout << (5 / 9.0) << endl;
    /// here we are doing int/float == float hence ouput should be float=0.5555
    int a;
    a = (5 / 9.0);
    cout << a << endl;
    a = (5.0 / 9.0);
    cout << a << endl;
    // in both the cases above we have the same thing but the ans which is float we are storing it in int 
    // hence 0.5555 reduced to 0
    a = (5 / 9.0) * 2;
    cout << endl;
    a = (5.0 / 9.0) * 2;
    cout << endl;
    /// in these above 2 case we are mutiplying the 0.555 with 2 result into 1. somthing which 
    // when stored in int result into 1
    float b;
    b = (5 / 0.9);
    cout << b << endl;
    // this is the correct way to store float nos in float bucket 
}

if you want to ask something about this feel free to ask
i hope this helps
if yes show your response with :heart: and don’t forgot to mark doubt as resolved