If we do 0^n we get n as the output, but why so? If n is int then does the bitwise operation occurs on 2^31 bits and then we get the number n as the output itself?
How do we get 0^n as n?
@raghav6 The result of XOR is 1 if the two bits are different. So XOR of 0 with any number n will always give n as output. Yes…the bitwise operation occurs on all the bits that data type can hold.
Consider unsigned char a = 5, b = 9;
So a = 5(00000101) and b = 9(00001001)
a^b= (00001100)
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