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#1

In the solution why are they including this condition. if(pq.size()==k) {
if(dist(x, y)<pq.top()) {
pq.pop();
pq.push(dist(x, y));
}

#2

@dips123deepali_c25f140838182212,
take the eq:
1 10 10
1 9 9
1 7 7
your pq will look
200
162
49
your ans now is 200
and now pq.size() == 3
query comes 1 5 5 now 25 < 200 so u need to pop first and then insert 25 so your pq will look
162
49
25
now if type 2 query comes then you can directly output 162 which is on top, if u haven’t removed 200 from top it would be on top

#3

Got it .Now I completely understand.

#4

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