Hint, How we can find product of all factors?

#1

as number is going to repeat on themselves power when multiply.

#2

The product of all the divisors of a number N is N^x where x is the number of divisors of N. The number of divisors is given by product of prime powers+1 for N. for example if N = 12 than its number of divisors are (2+1)*(1+1) = 6. you are already given the prime powers of N hence its number of divisors can be calculated.

#3

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