Here if (n&1) is doing that if it is true it is 1; and if it is not it is zero

#1

here if (n&1) is doing that if it is true it is 1; and if it is not it is zero

#2

hello @Aditya-Kushwaha-914550392281281
n&1 -> returns least significant bit of n . if least significant bit of n is 1 then n&1 will be 1 (or u can say true) otherwise n&1 will be 0(false).

if n is odd then n&1 will always be 1.
otherwise n&1 will be 0.

#3

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