#include
#include<math.h>
using namespace std;
int main() {
long long int n;
cin>>n;
long long int ans=0;
int a=0;
while(n>0){
int ld=n%10;
if(ld==0) ld=5;
ans+=ld*pow(10,a);
a++;
n/=10;
}
cout<<ans;
return 0;
}
#include
#include<math.h>
using namespace std;
int main() {
long long int n;
cin>>n;
long long int ans=0;
int a=0;
while(n>0){
int ld=n%10;
if(ld==0) ld=5;
ans+=ld*pow(10,a);
a++;
n/=10;
}
cout<<ans;
return 0;
}
hi @anshul3558_e8c9aa486c392ca3, what if n is 0 ??
handle that case separately
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n;
cin>>n;
long long int ans=0; //missing
int a=0;
if(n == 0)ans = 5;
while(n>0){
int ld=n%10;
if(ld==0) ld=5;
ans+=ld*pow(10,a);
a++;
n/=10;
}
cout<<ans;
return 0;
}
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