In the last part of the video , prateek tells that pointer a can be overwritten since it’s in the static memory , but array b can’t be overwritten.
I don’t get it, isn’t b also stored in the static memory?
Having trouble to understand the concept taught in the video
No as b is allocated memory during compile time!(RAM memory used)
a can be overwritten since it’s in the static memory
as a is allocated memory during runtime.(heap/static memory used)
So in what memory exactly are static variables stored?
Static variables are stored through compile time allocation , right?
Yes! see the problem is not with the memory but with the type of declaration!
when we declare int b[100], although b is a pointer, but it’s referencing address is fixed and we cannot change it!
but when we do int *b = new int[100], here b is a pointer, which is referenced to a memory address.
So in case 2 you can use b as a normal pointer but in case 1 you cannot.
Hope this helps.
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