Give me a hint of this question

#1

give me a hint of this question
i found the logic of how to replace the digits but i’m unable to change the number i.e x

#2

hi @utkarsh.gupta0311,
if digit is >5 flip that digit otherwise don’t flip
also check some corner cases
a) first digit should not be zero so if first digit is 9 then it should remain unchanged
b) if number is 0 only then output should be 9, not 0.

The logic behind this Problem was pretty simple as we can invert any digit ( 9 - digit) but we need to invert only such digits that will eventually end up giving the smallest number possible.

So, we should invert only digits greater then or equal to 5 as after inverting them, the result gives us smallest number.

For e.g.,

9 - 5 = 4 viz, smaller than the original number that was 5.

9 - 8 = 1 viz, smaller than the original number that was 8.

but 9 - 1 = 8 viz, greater than the original number that was 1.

Important point to consider is, After inverting any digits their should not be trailing zeros that means, if their is 9 at the starting of the number then it must remain the same

Also input can be quite big so, u need to capture the number in long long int in c++ and long in java.

for implementation difficulties refer https://ide.codingblocks.com/s/658154