Getting an extra zero in (n+1)th row

#1

#include
using namespace std;

int main(){
int n;
cin>>n;

int nst=1;
int nsp=2*n-1;
int nsta=1;
int j=2*n+1;
int csp;
int cst;
int row;
for(row=1;row<=j;row++){int i=n;
    for(cst=1;cst<=nst;cst++){
        cout<<i<<' ';
        i--;
    }
    for(csp=1;csp<=nsp;csp++){
        
        cout<<' '<<' ';
    }i++;
    for(cst=1;cst<=nsta;cst++){
		
        cout<<i<<' ';
        
        i++;
    }
    if(row<=n){
       
        
        nsp-=2;
        nst++;
          
        nsta++;
      
    }
    else{ 
        nsp+=2;
        nst--;
        
        nsta--;
    }
    cout<<endl;
}
cout<<endl;
return 0;

}

#2

hi @sanyamvv33_df49c435732e7baf
In Pattern Question, there is a common method which we teach in course viz, taking nsp, nst, csp, cst and row variables.

Pattern Hack : Always first Try to first print pattern by ignoring the value to be printed then accommodate your value in that pattern. For e.g.,

         5                   5 
         5 4               4 5 
         5 4 3           3 4 5 
         5 4 3 2       2 3 4 5 
         5 4 3 2 1   1 2 3 4 5 
         5 4 3 2 1 0 1 2 3 4 5 
         5 4 3 2 1   1 2 3 4 5 
         5 4 3 2       2 3 4 5 
         5 4 3           3 4 5 
         5 4               4 5 
         5                   5

View it as:-

         *                   * 
         * *               * * 
         * * *           * * * 
         * * * *       * * * * 
         * * * * *   * * * * * 
         * * * * * * * * * * * 
         * * * * *   * * * * * 
         * * * *       * * * * 
         * * *           * * * 
         * *               * * 
         *                   *

Short Info about the variables:-

1. nsp (number of spaces)-> Number of spaces in very First Line of the pattern.
2. nst (number of stars)-> Number of stars in very first line of the pattern.
3. csp (counter of spaces)-> counter of spaces that will print the required number of spaces and will be initialized with 1 and incremented upto nsp.
4. cst (counter of stars)->  counter of spaces that will print the required number of stars and will be initialized with 1 and incremented upto nst.
5. rows -> It will be initialized with 1 and will go upto the total number of rows in the pattern.

In the given pattern,

  • First build an intuition that u need to work for first row and at the end of the loop need to do work for the next row.
  • For each row first you need to print your pattern in decreasing order then spaces and then the same pattern but in increasing order.
  • To build the whole pattern just repeat this work according to total number of rows. With this approach, things seems to work out easily.
    refer this -->
    https://ide.codingblocks.com/s/646298
#3

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