Lets suppose that I have to calculate (A/B)%mod, can I reduce A and B using mod and then use mod - like ((A%mod)/(B%mod))%mod and then use multiplicative inverse property to solve?
General Doubt regarding modulus
hello @deep4013
the property is as follows->
(a/b) % mod = (a%mod * inverse of b % mod ) %mod
i dont think this will hold,
put B=mod and ur expression will be not define becuase denominator will be 0
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