g(z) = 1/(1+e^-z)
it’s differentiation is -e^-z((1+e^-z)^2)
but in the video he has not taken -ve sign and procceded by taking the wrong differentiantion. Will it not give wrong answer?
Finding value of g'(z)
Hey @abhayguptag7, you are missing one negative sign in the differentiation.
Hope this resolved your doubt.
Plz mark the doubt as resolved in my doubts section. 