Find Last Element | One Test Case Failing

#1

I have written the code, but one test case is failing. Can you help to identify which case is that?? I have checked for -ve numbers also.

import java.util.Scanner;

public class FindLastElement {

public static void main(String[] args){
	Scanner sc = new Scanner(System.in);
	String sizeofArray = sc.nextLine();
	String elementsofArray = sc.nextLine();
	String elementToSearch = sc.nextLine();
	int[] array = new int[Integer.parseInt(sizeofArray)];
	String[] result = elementsofArray.split("\\s");
	for (int x=0; x<result.length; x++)
     array[x] = Integer.parseInt(result[x]);
 
 
	System.out.println(findLastElement(array,Integer.parseInt(elementToSearch),0));

}

public static int findLastElement(int[] array, int numberToSearch, int selectedIndex){
	
	int result = -1;
	
	if(selectedIndex == array.length-1 ){
		if ( array[selectedIndex] == numberToSearch )
			return selectedIndex;
		else
			return result;
	}
		

	for( int x=selectedIndex; x<array.length-1; ++x){
		
		if( array[selectedIndex] == numberToSearch)
			result = selectedIndex;

		int currentresult = findLastElement(array,numberToSearch,x+1);
		if( currentresult != -1 )
		{
			result = currentresult;
		}
		
	}
	
	return result;
}

}

#2

Hey @connectrajanjain The test case you are failing here is :
5
6 9 3 9 0
9
As deeply observing the problem here is that after 5 in the first line there is a space. So if you try to take input using string and then convert the string to int that will give an error bcoz 5 plus a space is not an integer. So take input directly in the form of Int not in string.

#3

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